tentukan persamaan garis singgung yang melalui titik (-2,10) pada lingkaran (x-7)²+(y+2)²=225
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Jawaban:
PGSL
Sejajar 5y + 12x + 8 = 0
m = -koef x / koef y
=
m = -12/5
y- b = m(x-a) Ir (m? + 1)
y + 2 = -12/5 (x - 1) = 15V(169/25)
y + 2 = -12/5 (x - 1) + 39
=
:: 5y + 10 = -12x + 12 + 39
12x + 5y = 41
:: 5y + 10 = -12x + 12 - 39
12x + 5y = -37
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